4p^2-3p-45=0

Solution for 4p^2-3p-45=0 equation:

4p^2-3p-45=0

a = 4; b = -3; c = -45;
Δ = b2-4ac
Δ = -32-4·4·(-45)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-27}{2*4}=\frac{-24}{8}
=-3
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+27}{2*4}=\frac{30}{8}
=3+3/4
$